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Huge discussion of the original article: https://news.ycombinator.com/item?id=47746610 (781 points | 21 hours ago | 251 comments)

They only make some cubes?

Why are paths useful?


Does it handle pronunciation of different areas/countries?

> that's a huge advantage since you'll actually understand what you're talking about instead of just phonetically reading jargon

Do you have more technical details?


> The ad also highlights the salary on offer to controllers, saying it is $155,000 (£115,000) after three years of work.

IIRC they are understaffed and must do like 60hs per week, so it's like $103K in a sane work position.


I'd rename it puzzles -> questions .

After answering a question, the next question appears. It would be nice that the webapage goes to the top to be able to read the new question without scrolling.

[Question 1: I prefer something-something-decoherence. Which one should I select?]


I agree. I pressed space to fire and was surprised it pauses the game.

Did you write the game or only added the photos?

> The beauty here is that eml(x,y) is a pure, continuous analytical function with no hidden branching whatsoever.

They use the complex version of logarithm, that has a lot of branching problems.


Well, the paper explicitly takes the principal branch to solve this.

So it isn't exploiting the branching for computation.


Different sense of “branching”

Yep.

It transform a simple expression like x+y into a long chain of "eml" applications, so:

Derivatives: No. Exercise: Write the derivative of f(x)=eml(x,x)

Integrals: No. No. No. Integrals of composition are a nightmare, and here they use long composition chain like g(x)=eml(1,eml(eml(1,x),1)).


Agreed on integrals, but the derivative is relatively simple?

If f(x) = exp(x) - ln(x) then f’(x) = exp(x) - 1/x, which is representable in eml form as well.

To the overall point though, I don’t think it helps make derivatives easier though. To refactor a function to eml’s is far more work than refactoring into something that’s trivially differentiable with the product rule and chain rule.


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