Just for the record, let's count to 100 million. And add the numbers up while we're at it.
~ $ time (echo '(do (= n 0) (for i 1 100000000 (++ n i)) prn.n (quit))' | arc)
Welcome to Racket v5.3.5.1.
Use (quit) to quit, (tl) to return here after an interrupt.
arc> 5000000050000000
real 0m28.561s
user 0m28.308s
sys 0m0.249s
----
~ $ time (echo -e 'n=0 \ni=0 \nwhile (i <= 100000000): \n n += i \n i += 1 \n\nprint(n)\n' | python3.3)
5000000050000000
real 0m30.244s
user 0m30.230s
sys 0m0.013s
It would appear to be competitive with Python on my machine on this particular task. (Also you can make it faster by dropping into Racket.)
A while loop and temporary mutable variables are definitely not the Pythonic way of doing this. More idiomatic:
$ time python -c 'print sum(xrange(100000000 + 1))'
5000000050000000
real 0m1.398s
user 0m1.383s
sys 0m0.012s
Comparison to baseline:
$ time (echo -e 'n=0 \ni=0 \nwhile (i <= 100000000): \n n += i \n i += 1 \n\nprint(n)\n' | python)
5000000050000000
real 0m33.140s
user 0m32.939s
sys 0m0.023s
I see. That is good to know; I merely chose mutating global variables in a loop because I knew how to do that in both languages. (I am not very familiar with Python.) That is not the idiomatic way to do it in Arc, either. I would normally use a recursive function, like this:
arc> (time:xloop (i 0 n 0) (if (> i 100000000) n (next (+ i 1) (+ n i))))
time: 9121 cpu: 9130 gc: 0 mem: 480 ; the times are in msec
5000000050000000